« Annuité constante » : différence entre les versions

<math>F_n=E_n-\frac{A}{i}=-\frac{A}{i}=F_0(1+i)^n=(E_0-\frac{A}{i})(1+i)^n \Rightarrow A = E_0 \times\frac{i}{ 1-(1+i)^{-n} } \qquad </math><ref><math>-\frac{A}{i}=(E_0-\frac{A}{i})(1+i)^n \Rightarrow A = (A-E_0 \times i) (1+i)^n \Rightarrow </math><math>A(1-(1+i)^n)=-E_0\times i(1+i)^n \Rightarrow A=E_0 \times\frac{i(1+i)^n}{(1+i)^n -1 }=E_0 \times\frac{i}{ 1-(1+i)^{-n} }</math></ref>