lim n ← ∞ u n {\displaystyle \lim _{n\leftarrow \infty }u_{n}}
lim n ← ∞ 1 ( − 2 ) n = 0 {\displaystyle \lim _{n\leftarrow \infty }{\frac {1}{(-2)^{n}}}=0}
lim n ← ∞ sin ( α 0 − π 6 ( − 2 ) n + π 6 ) {\displaystyle \lim _{n\leftarrow \infty }\sin({\frac {\alpha _{0}-{\frac {\pi }{6}}}{(-2)^{n}}}+{\frac {\pi }{6}})}
<math>\lim_{n \leftarrow \infty} \sin (\frac \pi 6) = \frac \pi 6
